x^2=632

Solution for x^2=632 equation:

x^2=632

We move all terms to the left:

x^2-(632)=0

a = 1; b = 0; c = -632;
Δ = b2-4ac
Δ = 02-4·1·(-632)
Δ = 2528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2528}=\sqrt{16*158}=\sqrt{16}*\sqrt{158}=4\sqrt{158}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{158}}{2*1}=\frac{0-4\sqrt{158}}{2}
=-\frac{4\sqrt{158}}{2}
=-2\sqrt{158}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{158}}{2*1}=\frac{0+4\sqrt{158}}{2}
=\frac{4\sqrt{158}}{2}
=2\sqrt{158}
$